This has what to do with City of Heroes?
Seems like you would be better served by posting this to something like Yahoo Answers.
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Maybe check out Khan Academy (physics section) and see if they have a video that covers the subject. A great free learning resource.
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I would think it's just 100*cos(45). Although the object can't move along the y-axis, part of the force is still being applied in the y-direction, it's just being opposed by whatever is keeping the object in place along the y-axis.
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That matches my (admittedly somewhat shaky) memory of physics. Assuming a perfect restraint and no friction the Y component of the force would be canceled by an opposing force meaning that the net force on the object would be the X-component of the applied force.
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Originally Posted by DarkGob
I would think it's just 100*cos(45). Although the object can't move along the y-axis, part of the force is still being applied in the y-direction, it's just being opposed by whatever is keeping the object in place along the y-axis.
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If the force being applied is perpendicular to the X axis, then the X component of the force is zero and the object doesn't move. The situation is just like an object sitting on an ice skating rink, with gravity pressing it downward.
This sounds like a job for Arcanaville.
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That usually works for summoning the hero in the comics... 
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Hickman set the precedent of using he rule of three. For example, to summon Hickman usually requires writing Hickman three times in the post. |
Originally Posted by Twisted Toon
This sounds like a job for Arcanaville.
... ... That usually works for summoning the hero in the comics... |
Of course, you clould also try posting terms like "Defense Mechanics" or "Has Accuracy been Nerfed (Again)?"
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If the force is being applied by a second object pressing against a 45 degree incline, then 0.707 (half the square root of 2, from trigonometry) is applied perpendicular to the incline, so the movable object tends to resist that component. The component parallel to the incline is irrelevant to the object being pushed.
0.707 of that force ends up being parallel to the X axis, so the object is propelled by a net force in that direction of 0.707 x 0.707 = 0.5 times the weight (thrust, whatever) of the second object. This continues until the driving object falls off the end of the incline.
Defense is always nerfed.
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It's a pretty crappy illustration.
Wow, I completely misread the problem.
Guess I suck at word problems.
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Now solve via multiplication of vectors.
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This whole thread is a slap in the face.
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not really, i kind of understand why the OP would rather come here instead of yahoo answers or something|
Originally Posted by Eric Nelson
This whole thread is a slap in the face.
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from what ive seen 9/10 times poeple who do answer yahoo answers problems will say "we wont do your homework for you, your on your own" and dont even bother trying to help with pretty much any problem like this
i personally would prefer asking questions here, because everyone on the forums is pretty awesome, but since there is no specified section for stuff like this, i dont because of clutter since its not coh related. if there were a specified section for this type of stuff i would have used it a ton to help with writing papers since im terrible at that kind of stuff lol
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Um...way to completely miss the joke...
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Originally Posted by Necrotech_Master
not really, i kind of understand why the OP would rather come here instead of yahoo answers or something
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According to my calculations, the answer to your question is:
Akron, Ohio.
Okay, I suck at math.
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Easy enough, although I don't know why anyone would want to:|
Originally Posted by Zombie Man
Now solve via multiplication of vectors.
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Multiplication of Vectors
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I understood it like the Pengy answer in post 8. The Pengy drawing at 13 helps a little more.
My tiny pedantic comment is that 100 psi is pressure . Multiply by the area over which the pressure is being applied (in square inches) to get the total force.
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I had actually written a post pointing that out on the first day, then decided not to go there. |
Originally Posted by Fulmens
My tiny pedantic comment is that 100 psi is pressure.
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Can you give us more information? Most things I can think of in the real world that are measured in PSI would always apply the force perpendicular to the surface. That wouldn't prevent an instructor from creating a word problem that acted differently, however.
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My math skills have decayed so much that I don't even know where to start looking for the answer to this so if someone could help me out or even just point me in the right direction I'd appreciate it.
I'm trying to calculate the force exerted on object in a particular direction. The direction the force be applied would be perpindicular to the positive x axis on on graph in the positive y direction. The total force applied is equal to approximately 100 lb per square inch. The object would be fixed so that it could not move in either direction along the y axis. It can only move along the x axis. The object is set at a 45 degree angle. The question I'm trying to answer is how much force is being transfered to the object in the direction of the x-axis?
I'm sorry if my wording is confusing or imprecise. I've explained it as best I could.
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